Question

2÷x + 5lnx + l0e^x
find differentiation​

Answer 1

Explanation:

D of 2/x = ln x²

D of sinx = cosx

D of 10e^x = 10e^x itself

So, Differentiation is ln x² + cosx + 10e^x

Tell me what you have written in 2nd term....

Sinx or 5sinx ;)

Answer 2

Explanation:

$\sf \frac {2}{x} + 5ln x + 10{e}^{x}$

$\boxed{\bold{\red {\sf FORMULA = \frac{d ( {x}^{n} )}{dx} = n{x}^{n-1} }}}$

$\sf \frac{d(2{x}^{-1} )}{dx} = -2{x}^{-2} = \frac{-2}{{x}^{2}}$

$\boxed{\bold{\red{\sf FORMULA = \frac{d ( ln x) }{dx} = \frac{1}{x} }}}$

$\sf \frac{d(5lnx)}{dx} = \frac{5}{x}$

$\boxed{\bold{\red{\sf FORMULA = \frac{d ( {e}^{x} )}{dx} = {e}^{x} }}}$

$\sf \frac{d(10{e}^{x} }{dx} = 10{e}^{x}$

$\boxed{\bold{\red{\sf \frac{d ( \frac{2}{x} + 5lnx + 10{e}^{x}) }{dx} = \frac{-2}{{x}^{2}}+ \frac{5}{x} +10{e}^{x}}}}$

#JaibhavaniJaiShivaji