Question

2.
X
In the figure 7.44, O is the centre of
the circle. m(arc PQR) 60°
OP = 10 cm.
Find the area of the shaded region.
(n = 3.14, V3 = 1.73)​

Answer 1

Here, r = 10cm and θ = 60o Area of the shaded region = area of the segment = [ πθ360 - sin θ2 × cos θ2 ]r2 = [ 3.14 × 60360 - sin30o × cos30o ](10)2 ...

Top answer

Here, r = 10cm and θ = 60o Area of the shaded region = area of the segment = [ πθ360 - sin θ2 × cos θ2 ]r2 = [ 3.14 × 60360 - sin30o × cos30o ](10)2 ... More