Question

2 x minus 3 by 4 x square + 6 X Y + 9 y squar

Answer 1

Hope u like my process
=====================
Formula to be used
------------------------------
${x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ \\ or. \: \: {x}^{2} + xy + {y}^{2} = \frac{ {x}^{3} - {y}^{3} }{x - y}$
So...
$\frac{2x - 3y}{4 {x}^{2} + 6xy + 9 {y}^{2} } \\ \\ = \frac{(2x - 3y)}{ {(2x)}^{2} + 2x.3y + {(3y)}^{2} } \\ \\ = \frac{(2x - 3y)}{ \frac{ {(2x)}^{3} - {(3y)}^{3} }{(2x - 3y)} } \\ \\ = \frac{ {(2x - 3y)}^{2} }{8 {x}^{3} - 27 {y}^{3} } .....answer..$
Hope this is ur required answer.

Proud to help you