2 X raised to 4 - 3 x cube minus 3 X square + 6 x minus 2 / X square + - 2
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Answered by
7
Answer:
hence the factors are (x - √2) and (x+ √2) since x=√2 and x= -√2
if you multiply both you'll get x2 - 2
when you divide 2x4 - 3x3 - 3x2 + 6x - 2 by x2 - 2 since it is divisible by 2x4 - 3x3 - 3x2 + 6x - 2
the quotient will turn out to be 2x2 - 3x + 1
Now lets factorise this equation,
=>2x2 - 3x + 1=0
=>2x2 -2x -1x + 1 =0
=>2x(x - 1) -1(x - 1)=0
=>(2x - 1)(x - 1)=0
therefore 2x - 1=0 or x-1=0
which implies x=1/2 or x=1
here you have it the remaining two roots
Hope you get it
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Answered by
5
Answer:
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2x^4-3x^3-3x^2+6x-2x+(-2)
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