Question

2 x square -2 root 6 X + 3​

Answer 1

Answer:

${2x}^{2} - 2 \sqrt{6} x + 3 \\ = {( \sqrt{2} x)}^{2} - 2 \times \sqrt{2} x \times \sqrt{3} + {( \sqrt{3} )}^{2} \\ = {( \sqrt{2}x + \sqrt{3} ) }^{2} \\ = ( \sqrt{2}x + \sqrt{3} )( \sqrt{2}x + \sqrt{3} )$

Answer 2

Answer:

this is correct..........