Question

2 x square - 3(a+b)x+(a+b)^2 =0 solve by factorization​

Answer 1

Answer

The solutions of the equatind are

(a + b)/2 and (a + b)

Solution

Given , the quadratic equation

2x² - 3(a + b)x +(a+ b)² =0

Splitting the middle term

2x² - 2(a + b)x - (a + b)x + (a + b)²=0

⇒2x[x - (a + b)]-(a + b)[x -(a + b)]=0

⇒{2x - (a+b)}{x- (a+b)} = 0

Now the solutions are

2x - (a + b) = 0

⇒2x = a + b

⇒x = (a + b)/2

and

x - (a + b)=0

⇒x = a + b