Question

- 2 x square - 3 x + 20 divided / X + 4 ​

Answer 1

Step-by-step explanation:

see the attachment........

Answer 2

The answer of this question is $5-2x$.

Step-by-step explanation:

We are given with a quadratic equation which is divided by a linear equation,

$\frac{-2x^{2} -3x+20}{x+4}$

we have to find the answer of this division.

• Solving numerator

we have a quadratic equation in numerator so we can solve it by using factorization method.

numerator is $-2x^{2} -3x+20$

taking negative sign common from numerator,

$-(2x^{2} +3x-20)$

we can write $3x$ as $3x=8x-5x$ and $8x*(-5x)=-40x^{2}$ ,

$-[2x^{2} +8x-5x-20]$

taking common $2x$ from first two terms and $-5x$ from last two terms,

$-[2x(x+4)-5x(x+4)]$

we get the new numerator,

$-[(x+4)(2x-5)]$

• Division of simplified numerator by denominator

Now the numerator is $-[(x+4)(2x-5)]$

and denominator is $(x+4)$

division is,

$\frac{-[(x+4)(2x-5)]}{(x+4)}$

$(x+4)$ cancel out as it is present in both numerator and denominator side,

$-(2x-5)$

or  $5-2x$

We get the answer of this question as $5-2x$.