Question

2 x square + 9 x barabar 0

Answer 1

Solution :-

By using quadratic formula

$\implies \boxed{\sf x = \dfrac{ - b\pm \sqrt{ {b}^{2} - 4ac} }{2a}}$

Here

• a = 2
• b = 9
• c = 0

Substitute values in formula

$\implies \sf x = \dfrac{ - 9\pm \sqrt{ {9}^{2} - 4 \times 2 \times0} }{2 \times 2}$

$\implies \sf x = \dfrac{ - 9 \pm \sqrt{81} }{4}$

$\implies \sf x = \dfrac{ - 9 \pm 9 }{4}$

Taking +ve sign

$\implies \sf x = \dfrac{ - 9+9 }{4}$

$\implies \sf x = \dfrac{0}{4}$

$\implies \sf x =0$

Taking -ve sign

$\implies \sf x = \dfrac{ - 9 - 9 }{4}$

$\implies \sf x = \dfrac{ - 18}{4}$

$\implies \sf x = \dfrac{9}{2}$

★ Zeroes of equation are 0 and 9/2