Question

2 x square + x - 4 = 0 by quadratic formula ​

Answer 1

Answer:

Given:-

p(x) = 2x²+x-4

a= 2

b= 1

c= -4

To Find:-

Roots of p(x)

Quadratic Formula:-

D= b²-4ac

roots = (- b + √D)/2a

Solution:-

D = (1)²-4(2)(-4)

= 1+32

D = 33

roots = (-1 + √33)/2(2) = (-1 + √33)/4

therefore , roots of 2x²+x-4 are (-1+√33)/4 and (-1-√33)/4

Answer 2

Answer:

GIVEN:

2x^2+x-4=0

TO FIND:

ROOTS OF THIS QUADRATIC EQUATION BY QUADRATIC FORMULA.

QUADRATIC FORMULA:

D=b^2-4ac

Roots=(-b+root d)/2a

SOLUTION:

a=2

b=1

c=4

NOW ACCORDING TO FORMULA,

D=1^2-4×2×(-4)=1+32=33

ROOT= -1+ROOT 33/4

SO THE ROOTS ARE;

$\frac{ - 1 + \sqrt{33} }{4} \\ \\ \frac{ - 1 - \sqrt{33} }{4}$