2 X square + Y square + 6 x minus 2 X Y + 9 is equal to zero then find the value of 4 x cube minus y cube + x square y square
Answers
Answered by
0
Answer:(
1+
3
4
2
)(
1−
3
4
+
3
16
1−
3
4
+
3
16
)
= \dfrac{2\,\left(1 - \sqrt[{\scriptstyle 3}]{4\,} + \sqrt[{\scriptstyle 3}]{16\,}\right)}{\left(1 + \sqrt[{\scriptstyle 3}]{4\,}\right)\left(1 - \sqrt[{\scriptstyle 3}]{4\,} + \sqrt[{\scriptstyle 3}]{16\,}\right)}=
(1+
3
4
)(1−
3
4
+
3
16
)
2(1−
3
4
+
3
16
)
= \mathbf{\color{purple}{ \dfrac{2 - 2\,\sqrt[{\scriptstyle 3}]{4\,} + 4\,\sqrt[{\scriptstyle 3}]{2\,}}{5} }}=
5
2−2
3
4
+4
3
2
Step-by-step explanation:
Similar questions