Question

(-2-x)whole sq plsss aannsweerrr​

Answer 1

     

$\Rightarrow\ (-2-x)^2 \\ \\ \Rightarrow\ (-(x+2))^2 \\ \\ \Rightarrow\ (x+2)^2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [\because\ (-a)^2=a^2] \\ \\ \Rightarrow\ x^2+4x+4 \\ \\ \\ \\ \\ Thank you. :-))$

       

Answer 2

here is ur answer:

${( - 2 - x)}^{2} = {(( - 2) + ( - x))}^{2} \\ \\ { (- 2)}^{2} + {( - x)}^{2} + 2 \times - 2 \times - x \\ \\ 4 + {x}^{2} + 4x \\ \\ {x}^{2} + 4x + 4$

hope it helps you!