2(x²+1)=5x please give answer with full solution as fast as can please!!!
Answers
Answer:
2(x^2+1)=5x
2x^2 +2 -5x = 0
2x^2-5x+2=0
2x^2 -4x -x+2=0
2x(x-2)-1(x-2)=0
(2x-1)(x-2)=0
zeroes
2x-1 =0
x= 1/2
x-2=0
x=2
Step-by-step explanation:
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Solution!!
→ 2(x² + 1) = 5x
Distribute 2 through the parentheses.
→ 2x² + 2 = 5x
Move the variable to the left-hand side and change its sign.
→ 2x² + 2 - 5x = 0
Use the commutative property to reorder the terms.
→ 2x² - 5x + 2 = 0
Write -5x as a difference.
→ 2x² - x - 4x + 2 = 0
Factor out x from the expression.
→ x(2x - 1) - 4x + 2 = 0
Factor out -2 from the expression.
→ x(2x - 1) - 2(2x - 1) = 0
Factor out 2x - 1 from the expression.
→ (2x - 1) (x - 2) = 0
When the product of factors equals 0, at least one factor is 0.
→ 2x - 1 = 0
→ x - 2 = 0
Solving the equations for x.
→ x = 1/2
→ x = 2
Hence, we have 2 values of x.