Question

2*x²-x+⅛ by factorization

Answer 1

$2 {x}^{2} - x + \frac{1}{8} \\ = \frac{16 {x}^{2} - 8x + 1 }{8} \\ = \frac{16 {x}^{2} - 4x - 4x + 1 }{8}$


$= \frac{4x(4x - 1) - 1(4x - 1)}{8} \\ = \frac{(4x - 1)(4x - 1)}{8} \\ = \frac{4x - 1}{8} \times (4x - 1)$
$= ( \frac{x}{2} - \frac{1}{8} )(4x - 1)$