Question

2 years ago a man's age was 3 times the square of his son's age .3 years hence his age will be 4 times his son's age .find their present ages

Answer 1

These are simultaneous equations
[tex]m-2=3(s-2)^2 [/tex]
$m+3=4(s+3)$
Where m is the man's age and s is the son's age
$m=3(s-2)^2+2$
$m=4(s+3)-3$
Therefore
$3(s-2)^2+2=4(s+3)-3$
By the time you solve it you will get s=5
But
$m=4(s+3)-3$
$m=4(5+3)-3$
$m=29$
Therefore the man is 29 and the boy is 5.

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