Question

2 years ago a mans age was 3 times the square of his son age after 3 years his age will be 4 time his son age .find the present age

Answer 1

Let the age of Son 2year ago = x

Present age of son=x+2

Father=3x²

Present age of father =3x²+2

After 3 year,

(X+5)4=(3x²+5)

4x+20=3x²+5

3x²-4x-15=0

3x²-9x+5x-15=0

(3x+5)(x-3)=0

So x=3

Son=x+2=3+2=5

Father =3x²+2=3*9+2=29