2 years ago, Dilip was three times as old as his son and 2 years hence, twice his age will be equal to five times that of his son. Find their present age?
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Answered by
434
2 years ago,
Son's age = x
Dilip's age = 3x
Present age of Son = x+2
Present age of Dilip = 3x+2
After 2 years,
Son's age = x+2+2 = x+4
Dilip's age = 3x+2+2 = 3x+4
A/Q 2(3x+4) = 5(x+4)
6x+8 = 5x+20
x = 12
∴ Present age of son = x+2 = 12+2 = 14
Present age of Dilip = 3x+2 = 3x12+2 = 38
Son's age = x
Dilip's age = 3x
Present age of Son = x+2
Present age of Dilip = 3x+2
After 2 years,
Son's age = x+2+2 = x+4
Dilip's age = 3x+2+2 = 3x+4
A/Q 2(3x+4) = 5(x+4)
6x+8 = 5x+20
x = 12
∴ Present age of son = x+2 = 12+2 = 14
Present age of Dilip = 3x+2 = 3x12+2 = 38
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Because the question says that twice the age of Dilip will be equal to five times the age of his son.
Answered by
103
Answer:
Step-by-step explanation:
Let the age 2 yrs ago
Son =x
Dilip =3x
Present age
Son= x+2
Dilip =3x+2
Age after 2 yrs
Son =x+2+2 =x+4
Dilip =3x+2+2=3x+4
According to question
5(x+4)=2(3x+4)
5x+20=6x+8
5x-6x=8-20
-x=-12
Negative negative cancel
x=12
Present age of son =12+2=14
Present age of Dilip =3 *12+2=36+2=38
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