Question

2 years ago Dilip was three times as old as his son and two years hence twice his age will be equal to five times that of his son find their present age

Answer 1

Dilip age was three times as old as his son

D = 3S

two years hence, twice his age will be equal to five times that of his son.

2(D + 2) = 5(S + 2)

Replace D on left hand side with 3S

2(3S + 2) = 5(S + 2)

6S + 4 = 5S + 10

6S - 5S = 10 - 4

S = 6.

Dilip is aged 20 years old

Son is 8 years old

Hope this helps.

:-)

Answer 2

Given :-

→ Let Dilip's son's age 2 years ago be x years.

Then, Dilip's age 2 years ago = ( 3x ) years

Thus , the son's age 2 years hence (x + 4) years.

Dilip's age 2 years hence (3x + 4) years.

→ 2 ( 3x + 4 ) = 5 ( x + 4 )

→ 6x + 8 = 5x +20

→ x = 12.

∴ Dilip's son's age 2 years ago = 12 years and Dilip's age 2 years ago = 36 years.

∴ son's present age = 14 years, and

Dilip's present age = 38 years.

Thank You!