Question

An object is placed at a distance of any and half of the focal length of a concave mirror. Find the position of the image in terms of "f". Also find the magnification and nature of the image formed.

Answer 1

Hey friend!!


Here's ur answer..


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Object distance = - f/2
Focal length = f

Using mirror formula :

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \\ \\ \frac{1}{f} = \frac{1}{v} + \frac{2}{f} \\ \frac{1}{v} = \frac{1}{f} - \frac{2}{f} \\ \frac{1}{v} = - \frac{1}{f} \\ v = - f$
So, image distance = - f


Magnification =-v/u
$= \frac{ - v}{u} \\ = \frac{ - ( - f)}{f} \\ = \frac{f}{f} \\ = 1$
So, Magnification = 1

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Hope it may help you...


Thank you :) :))