Math, asked by kt3078673, 2 months ago

2 years ago, father's age was 9 times the son's age but 3 years later it will be 5 times only. Find the present age of son and father.​

Answers

Answered by doofuzz
0

Answer:

father is 47 and son is 7

try to verify it also

Answered by profdambaldor
11

Answer:

Present age of father = 47 Years

Present age of Son = 7 Years

Step-by-step explanation:

Let's the present age of son is x and present age of father is y.

2 years before:

Father's age = y-2

Son's age = x-2

According To Question:

y - 2 = 9(x-2)

y = 9x - 18 + 2 = 9x -16        -------------------(1)

3 years later:

fathers's age = y + 3

son's age = x + 3

According to Question:

y + 3 = 5*(x+3)

y = 5x + 15 - 3 = 5x + 12   --------------------------(2)

from (1) and (2)

9x - 16 = 5x + 12

⇒4x = 28

⇒x = 7

so, from (1)

y = 9*7 - 16 = 63 - 16 = 47

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