Question

2 years ago Sahil was 3 times older than his son and after 2 years his age would be double his son's age 5 times. Find his current age. Check the solution.​

Answer 1

Answer:

sahils age=67

son's age= 17

Step-by-step explanation:

Answer 2

$\huge\bf\underline\green{SOLUTION⇊}$

$\small\bf\underline{↦let \: the \: age \: of \: son=χ}$

$\small\bf\underline{↦let \: the \: age \: of \: sahil=ყ}$

$\huge\sf\underline{THEN:-}$

$\small\sf{2 \: years \: ago,}$

$\small\sf{ყ-2=3(x-2)}$

$\small\sf{ყ-2=3x-6}$

$\small\sf{ყ=3x-4}$

$\huge\sf\underline{Equation(1)↥}$

$\small\sf{after \: 2 \: years,}$

$\small\sf{2(ყ+2)=5(x+2)}$

$\small\sf{2ყ+4=5x+10}$

$\small\sf{2ყ=5x+6}$

$\huge\sf\underline{Equation(2)↥}$

$\small\bf\underline \green{↦Solving \: equation(1) \: and \: (2)}$

$\small\sf{2(3x-4)=5x + 6}$

$\small\sf{6x-8=5x+6}$

$\small\sf{x=14}$

$\small\sf{ყ=3x-4}$

$\small\sf{=3(14)-4}$

$\small\sf{=42-4}$

$\small\sf{=38}$

Present ages of father-son duo is 38 of father and 14 of son.