Question

20.0 g of a magnesium carbonate sample decomposes on heating to give CO₂ and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample?

Answer 1

Answer:

Explanation:

So, we have to calculate, how much pure MgCO3 is needed to produce 8⋅0 mg of MgO on heating. Hence, option (C) is the correct answer, 80% is the percentage purity of magnesium carbonate in the sample.

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Answer 2

QUESTION

• 20.0 g of a magnesium carbonate sample decomposes on heating to give CO₂ and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample?

EXPLANATION

The chemical reaction involved :-

MgCO₃ ---> MgO + CO₂

84 g of MgCO₃ form 40 g of MgO

20g of MgCO₃ form = (40 * 20) / 84 g of MgO

= 9.52 g of MgO

Since 8 g of MgO is formed

Purity = (8 / 9.52) × 100 = 84%