Chemistry, asked by Jay123654, 10 months ago

20.0 g of magnesium carbonate sample decomposes on heating to give carbon dioside and 8.0 g of MgO .What will be the % purity of Magnesium carbonate in the sample?

Answers

Answered by Ruchi333
9

Answer:

MgCo3 - - - > Mg + CO2

84g 40g

Yg be 8g (y is variable used)

Y=(84*8)/40=16.8g

Percentage purity of MgCo3 = (16.8*100)/20=84%

Hope will help you...........!!!

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