Question

2x^2-2x+1/2=0 solve the equation by factorisation​

Answer 1

Answer:

I hope it would help you

Answer 2

Answer:

$\large x=\dfrac{1}{2}$

Step-by-step explanation:

Given :

$\large p(x)=2x^2-2x+\dfrac{1}{2}=0$

We have to factorise the p ( x ).

By splitting mid term method we have

$\large p(x)=2x^2-2x+\dfrac{1}{2}=0\\\\\\\large p(x)=2x^2-x-x+\dfrac{1}{2}=0\\\\\\\large p(x)=x(2x-1)-\dfrac{1}{2}(2x-1) =0\\\\\\\large p(x)=(2x-1)(x-\dfrac{1}{2})=0$

Zeroes of p ( x )

$\large p(x)=(2x-1)(x-\dfrac{1}{2})=0\\\\\\\large (2x-1)=0 \ or \ (x-\dfrac{1}{2})=0\\\\\\\large (2x)=1 \ or \ (x)=\dfrac{1}{2}\\\\\\\large x=\dfrac{1}{2}\\\\\\\large \text{So both value of x =\dfrac{1}{2} }$

Thus we get answer.