20.0 mL of dilute HNO3 is neutralised completely with 25mL of 0.08 M NaOH. What is the molarity of HNO3?
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Answer:According to volumetric law, N1V1=N2V2
In this problem, normality is equal to molarity for HNO3 and NaOH. Therefore, M1V1=M2V2
M1=Molarity of HNO3, V1=20 mL, M2= Molarity of NaOH=0.08M, V2=25 mL
On substitution
M1 x 20 = 0.08 x 25
or Molarity of HNO3, M1 = 0.08 Mx 25 mL/20 mL = 0.1 M
Explanation:
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