Question

20+15/3y−1= 11

pls need ans fast

Answer 1

Answer:

$\frac{20 + 15}{3y - 1} = 11 \\ 20 + 15 = 11(3y - 1) \\ 35 = 33y - 11 \\ 35 + 11 = 33y \\ 46 = 33y \\ \large{ \boxed{ \underline{ \underline{\frac{46}{33} }} = y }}\\ \\ \large{\underline{Let's \: \: verify} :}\\ \frac{20 + 15}{3y - 1} = 11 \\ \frac{35}{(3 \times \frac{46}{33} ) - 1} = 11 \\ \frac{35}{ \frac{46}{11} - 1 } = 11 \\ \frac{35}{ \frac{46 - 11}{11} } = 11 \\ \frac{35}{ \frac{35}{11} } = 11 \\ 35 \times \frac{11}{35} = 11 \\ \large{ \boxed{\underline{ \underline{11 = 11}}}} \\ \\ \large{Hence, \: \: Verified}$