Question

20(15 + 5p) = 295+ 100p + 5p^2

Answer 1

Answer:

p= 1 , -1

Step-by-step explanation:

    20(15 +5p) = 295 + 100p + 5p^2

=> 20(15+5p) = 5(59 + 20p +p^2)

=>  4(15+5p) = 59 + 20p+ p^2

=>  60+20p = 59 +20p + p^2

=>   p^2 - 1 = 0

=>   (p+1) (p-1) = 0   [we know that x^2 - y^2 = (x+y)(x-y)]

therefore, on equating both (p+1) & (p-1) from 0=

p = 1 & -1