Question

20,23,29,38,50,65,104​

Answer 1

$Given \: sequence: \\20,23,29,38,50,65, \red{?},104$

$Observe \:the \: pattern \:of \:the \: sequence ,$

$First \:term = 20$

$Second \:term = 20+ \blue{3\times 1 } = 23$

$Third \:term = 23+ \blue{3\times 2 } =23+6= 29$

$Fourth \:term = 29+ \blue{3\times 3 } = 29+ 9 = 38$

$Fifth \:term = 38+ \blue{3\times 4 } =38+12 = 50$

$Sixth \:term = 50+ \blue{3\times 5 } = 50+ 15 = 65$

$\pink {Sixth \:term} = 65+ \blue{3\times 6 } = 65+ 18 =\pink { 83}$

$Seventh\:term = 83 + \blue{3\times 7 } = 83+ 21 = 104$

Therefore.,

$\red{ Missing \:term } \green { = 83}$

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