20 ,32 ,48 find the HCF by long division method
Answers
Answer:
HCF= 4
HOPE IT WILL HELP U
The HCF of the given numbers 20, 32, and 48 by long division method is 8.
To find the highest common factor (HCF) of the given numbers 20, 32, and 48 by long division method, we can follow these steps:
Step 1: Write the given numbers in a horizontal row.
20 32 48
Step 2: Find a number that divides all the given numbers evenly.
Start with 2, which is the smallest prime number, and check if it divides all the given numbers without leaving any remainder.
20 32 48
---- ---- ----
| 2 | | |
| | 2 | |
| | | 2 |
---- ---- ----
10 16 24
Step 3: Divide each number by 2, and write the quotients below the numbers.
20 32 48
---- ---- ----
| 2 | | |
| | 2 | |
| | | 2 |
---- ---- ----
| 10 | 16 | 24 |
Step 4: Repeat Step 2 and Step 3 with the new set of numbers until no number can be divided further.
10 16 24
---- ---- ----
| 2 | | |
| | 2 | |
| 5 | | 2 |
---- ---- ----
| 5 | 8 | 12 |
---- ---- ----
| | 2 | |
| | | 2 |
| | 4 | 6 |
---- ---- ----
| | 2 | |
| | | 2 |
| | 2 | 3 |
---- ---- ----
Step 5: The HCF is the product of all the divisors used in Step 2, with each divisor used once.
In this case, the divisors used are 2, 2, and 2. Therefore, the HCF of 20, 32, and 48 is:
HCF = 2 x 2 x 2 = 8
Therefore, the HCF of the given numbers 20, 32, and 48 by long division method is 8.
For similar question on Long division method.
https://brainly.in/question/21291851
#SPJ2