20/4 is divided into two parts such that 7 times the first part added to 5 times the second part is 146. find each part
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let first part be x
then second part be 5-x (20/4-x)
acc/que
7x+5(5-x)= 146
7x+25-5x=146
2x+25=146
2x=146-25
2x= 121
x=121/2
x= 60.5
first part = 60.5
second part is - 55.5
then second part be 5-x (20/4-x)
acc/que
7x+5(5-x)= 146
7x+25-5x=146
2x+25=146
2x=146-25
2x= 121
x=121/2
x= 60.5
first part = 60.5
second part is - 55.5
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