Question

20. A block of mass 5 kg lies on a horizontal table. The block is at rest. The only forces acting on the block are the force due to gravity and the normal force from the table. What is the magnitude of the friction force?

Answer 1

Friction force = Coefficient of friction x mg
Let the coefficient be α.
f = α x 5 x 10 = α x 50
Since, coefficient is not given here, we will keep α as it is.
So, the answer will be
α x 50 N.

Thanks.