20. A bullet fired from a gun experiences a force of
600 - 2 x 10$t in the barrel of the gun. Here is
in second. The force becomes zero as soon as the
bullet leaves the barrel of the gun. The time for
which the bullet was in the barrel of the gun is
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Explanation:
The force on the bullet is given by F = 600 - 2 × 10^5t , where F is in N and t in sec. The force on bullet becomes zero as soon as it leaves barrel.
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