Question

20. A sodium salt on treatment with MgCl2 gives white precipitate only on heating. The
anion of the sodium salt is
(a) HCO3 (b)CO:
(c) NO, (d) SO.​

Answer 1

Answer:

☞HCO-³

explanation:

The salt will be sodium bicarbonate and the anion is HCO-³

When sodium bicarbonate react with MgCI² it produce Magnesium bicarbonate which is also soluble in water

But, on heating Mg (HCO³) it produce Mg(CO³) which gives white precipitate

Mg(HCO³)²➝ Mg(CO³) + CO² + H²o

Answer 2

HCO-³

Explanation:

The salt will be sodium bicarbonate and the anion is HCO-³

When sodium bicarbonate react with MgCI² it produce Magnesium bicarbonate which is also soluble in water

But, on heating Mg (HCO³) it produce Mg(CO³) which gives white precipitate

Mg(HCO³)²➝ Mg(CO³) +

CO² + H²o

Hope it's helpful