20 divisions of VSD coincides with 15 divisions of MSD and 1 MSD = 1 cm then least count will be ?
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The least count of the Vernier calipers is 0.1mm.
LC=0.1mmLC=0.1mm
We have given that there are 20 divisions on the Vernier scale and one of the line on the Vernier scale coincide with the 19th line on the main scale of the Vernier calipers.
Hence, the value of the one Vernier scale division becomes
1VSD=1920MSD1VSD=1920MSD
We have the formula for least count as
LC=1MSD−1VSDLC=1MSD−1VSD
Here,
MSDMSD
is the value of one main scale division on Vernier calipers and
VSDVSD
is the value of the one Vernier scale division on Vernier caliper.
Substitute
1920MSD1920MSD
for
1VSD1VSD
in the above equation.
LC=1MSD−1920MSDLC=1MSD−1920MSD
⇒LC=120MSD⇒LC=120MSD
Substitute
0.1mm0.1mm
for
LCLC
in the above equation.
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