Physics, asked by justiceforssr06, 6 hours ago

20 divisions of VSD coincides with 15 divisions of MSD and 1 MSD = 1 cm then least count will be ?​

Answers

Answered by janvisingla81066
0

Answer:

Complete step by step answer:

The least count of the Vernier calipers is 0.1mm.

LC=0.1mmLC=0.1mm

We have given that there are 20 divisions on the Vernier scale and one of the line on the Vernier scale coincide with the 19th line on the main scale of the Vernier calipers.

Hence, the value of the one Vernier scale division becomes

1VSD=1920MSD1VSD=1920MSD

We have the formula for least count as

LC=1MSD−1VSDLC=1MSD−1VSD

Here, 

MSDMSD

 is the value of one main scale division on Vernier calipers and 

VSDVSD

 is the value of the one Vernier scale division on Vernier caliper.

Substitute 

1920MSD1920MSD

 for 

1VSD1VSD

 in the above equation.

LC=1MSD−1920MSDLC=1MSD−1920MSD

⇒LC=120MSD⇒LC=120MSD

Substitute 

0.1mm0.1mm

 for 

LCLC

 in the above equation.

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