20 Find the nature of the roots of the quadratic equation X -5x -10 = 0
Answers
Answered by
2
Comparing the given polynomial with ax²+bx +c =0
a=1, b=-5 and c= -10
D= b²-4ac
= (-5)²-4(1)(-10)
= 25+40
= 65
D>0
Therefore, the given polynomial has two distinct real roots.
Answered by
1
Step-by-step explanation:
x-5x-10=10
the given equation is in the form of ax2+bx+c=0
where,
a=1
b=-5
c=-10
therefore the discriminant
b2-4ac
(-5)²-4×1×(-10)
25+40
65
hence,
two distinct real roots
hope this helps u✌️
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