Question

If two zeroes of polynomial P(x)=x^3+2x^2-9x-18 are 3 and -3 , find other zero of the polynomial​

Answer 1

Answer:

the other zero of the polynomial is minus two.

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Answer 2

$\bf{\underline{\underline{Given\: :}}}$

$\mathsf{\bigstar\: P(x) = x^{3} + 2x^{2} - 9x - 18}$

$\mathsf{\bigstar \: Zeroes\: are\: 3\:\:and\:\: (-3)}$

$\bf{\underline{\underline{To\:find\: :}}}$

$\mathsf{\bigstar\: Other \:zero \:of \:P(x) }$

$\bf{\underline{\underline{Solution\: :}}}$

$\mathsf{Let \: us\: represent\: the\:zeroes\: as \:\: "x"}$

$\mathtt{\rightarrow\: x = 3\: , \: (-3)}$

$\mathtt{\rightarrow\: (x - 3)(x + 3) = 0}$

$\mathtt{\rightarrow\: x^{2} + \cancel{3x} - \cancel{3x} - 9 = 0}$

$\mathtt{\rightarrow\: x^{2} - 9 = 0}$

$\mathsf{On\:dividing\:p(x)\:by\:\:( x^{2} - 9)\: :}$

$\mathtt{We\:get\: \implies\: (x + 2) }$

$\fbox{\Large{\mathtt{\green{\implies\: x = (-2) }}}}$

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