20. Find the value of k, when roots of the x^ - 6x + k = 0 are real and equal.
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Answered by
3
Answer:
If roots are real and equal
then D=0
a=1, b=-6, c=k
b²-4ac=0
(-6)²-4×1×k=0
36-4k=0
-4k=-36
k=9
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Answered by
1
x²- 6x+ k= 0
a= 1, b= 6 and c= k.
If the roots are equal and real then D= 0.
D = b² - 4ac
(-6)² - 4×1×k = 0
36 - 4k = 0
-4k = -36
k= 9.
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