Question

20. Find the value of x2 + 1 2 , if x – 1 = √3.

Answer 1

Answer:

$x - 1 = \sqrt{3}$

$x = \sqrt{3} + 1$

$2( \sqrt{3} + 1) + 12$

$2 \sqrt{3} + 2 + 12$

$2 \sqrt{3} + 14$

2(1.7320508076+1)+14

19.4641016152

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Answer 2

Answer:

if x -1 = $\sqrt{3}$

x = $\sqrt{3}$ + 1

substituting in $x^{2}$ + 12

= $(\sqrt{3} + 1 )^{2}$ + 12

= $(\sqrt{3} )^{2}$ + 1 + 2$\sqrt{3}$ + 12

= 3 + 1 + 2$\sqrt{3}$ + 12

= 16 + 2$\sqrt{3}$

= 16 + 2 x 1.732050808

= 16 + 3.464101615

= 19.46410162