Question

The motion of a particle is described by the equation V=2t. Find the distance travelled by the particle in the first 4 seconds?​

Answer 1

Answer:

here is your is your answer to the question

Answer 2

Answer:

16 units

Explanation:

V=2t (Given)

So, when t=0 (i.e initial point)

V=0m/s

When t= 4 (final point)

V=2*4 = 8m/s

a=v-u/t

Plugging in the values, we get:

a=8-0/4

=2m/s^2

Using Newtons Second Equation of motion, we get:

s=(0)(0)+ 1/2*2*(4)^2

=16 m

Hope this helps.. :D