20 find the value of x3 +y3-12xy+64when x+y=-4
Answers
Answered by
0
Answer: x³ + y³ - 12xy + 64
x³ + y³ + 4³ - 3(4xy) (64 = 4³)
(x + y + 4)(x² + y² + 4² - xy - 4y - 4x)
x + y = - 4
(- 4 + 4) * (x² + y² + 4² - xy - 4y - 4x)
0 * (x² + y² + 4² - xy - 4y - 4x)
= 0
Step-by-step explanation:
Similar questions