Question

20 g of steam initially at 100 degree C is added to 60 g of ice at 0 degree C,Find the final equilibrium temperature of the mixture.

Answer 1

Answer:

The final equilibrium temperature is 298 K or 25 C.

Explanation:

• We have the formula $T = \frac{(m1*T1)+(m2*T2)}{m1+m2}$

• Where T is the equilibrium temperature.
• m1 is mass of first fluid. m2 is the mass of second fluid.
• T1 is the temperature of first fluid. T2 is the temperature of second fluid.
• Substituting the given data, we have:
• m1 = 20 g; T1 = 100 C
• m2 = 60 g; T2 = 0 C
• T = (2000+0)/(20+60)
• T = 25 C