Question

20 g sodium hydroxide in 2lt of aqueous solution. Find the strength in mol/l unit​

Answer 1

Answer:

NaOh-molar mass-40 g

Number of moles in NaOh-20/40=0.5(given mass/molarmass)

Molarity=moles of solute /volume of solution in litre=0.5/2=0.25 mol/l

Answer 2

Mass of NaOH=20g

Molar mass of NaOH=40g

No of moles

=Mass/Molar mass

=20/40

=0.5 moles

Volume of soln=2 L

Molarity

=Moles of NaOH/vol of soln

=0.5/2

=0.25mol/litre