Question

20. If A If A={x/x^2 =-1, xe R}, then n(p(A))
=​

Answer 1

Given, f(x)=x

Given, f(x)=x 2

Given, f(x)=x 2

Given, f(x)=x 2 ∴

Given, f(x)=x 2 ∴ (1.1−1)

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1)

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1)

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) =

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1)

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1)

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1) 2

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1) 2

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1) 2

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1) 2 =

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1) 2 = 0.1

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1) 2 = 0.11.21−1

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1) 2 = 0.11.21−1

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1) 2 = 0.11.21−1 =

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1) 2 = 0.11.21−1 = 0.1

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1) 2 = 0.11.21−1 = 0.10.21

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1) 2 = 0.11.21−1 = 0.10.21

Given, f(x)=x 2 ∴ (1.1−1)f(1.1)−f(1) = (1.1−1)(1.1) 2 −(1) 2 = 0.11.21−1 = 0.10.21 =2.1

thanks for points