Question

20. If tan 0 = cot (30° + n), find the value of 0.​

Answer 1

ANSWER:

Given

tanθ = cot(30° + θ)

We know that

cotθ = tan(90° - θ)

tanθ = tan[90° - (30° + θ)]

tan = tan (60° - θ)

θ = 60° - θ

2θ = 60°

θ = 60°/2 = 30°

MORE INFORMATION:

sin(90° - θ) = cosθ

cos(90° - θ) = sinθ

tan(90° - θ) = - cotθ

cosec(90° - θ) = secθ

sec(90° - θ) = cosecθ

cot(90° - θ) = tanθ