Question

20. If (x+y) =11 and xy =2 ,
then find value of x^2 + y^2​

Answer 1

x2+ye =73

Step-by-step explanation:

x+y=11

on squaring both sides

(x+y)2=(11)2

x2+ye+2xy=121

x2+ye+2*24=121

x2+ye=121-48

x2+ye=73

Answer 2

Answer:

$x + y = 11$

Step-by-step explanation:

$xy = 2$

${(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy$

${11}^{2} = {x}^{2} + {y}^{2} + 2 \times 2$

${x}^{2} + {y}^{2} = 121 - 4 = 117$