20 litre of SO2 diffuses through a porous partition in 60 seconds. Volume of O2 diffuse under similar conditions in 30 seconds will be?
A) 12.41 litres
B) 14.14 litres
C) 18.14 litres
D) 28.14 litres
Answers
Answered by
135
The answer is 14.14 Litres.
Given: Volume of SO2=20 liter, Time taken for diffusion by SO2= 60 sec, Time taken for diffusion by O2= 30 sec.
To find: Volume of O2
Solution:
Let the volume of O2 be V
Rate of diffusion of SO2=20/60=1/3
Rate of diffusion of O2=V/30
We know, r1/r2=root of m2/root of m1 (where m1 and m2 are the molecular masses)
1/3/V/30=square root of 32/square root of 64
1/3* root 2=V/30
10*root 2=V
10*1.414=V
14.14 litres=V
i.e Volume of O2 is 14.14 litres
Given: Volume of SO2=20 liter, Time taken for diffusion by SO2= 60 sec, Time taken for diffusion by O2= 30 sec.
To find: Volume of O2
Solution:
Let the volume of O2 be V
Rate of diffusion of SO2=20/60=1/3
Rate of diffusion of O2=V/30
We know, r1/r2=root of m2/root of m1 (where m1 and m2 are the molecular masses)
1/3/V/30=square root of 32/square root of 64
1/3* root 2=V/30
10*root 2=V
10*1.414=V
14.14 litres=V
i.e Volume of O2 is 14.14 litres
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