Question

20 men can prepare 40 toys in 24 days working 18 hours a day. then in how many days can 36 men prepare 48 toys working 16 hrs a day? ​

Answer 1

Answer:

p.o.m=p.o.e

point of means=point of extreme

ans is 18 days

Answer 2

36 men can prepare 48 toys in 18 days working 16 hrs a day

Step-by-step explanation:

Let $M_1$be the no. of men , $W_1$ be the no. of boys , $D_1$ be the no. of days and $H_1$ be the no. of hours.

We are given that 20 men can prepare 40 toys in 24 days working 18 hours a day.

$M_1=20\\W_1=40\\D_1=24\\H_1=18$

Now we are supposed to find  how many days can 36 men prepare 48 toys working 16 hrs a day? ​

Let $M_2$be the no. of men , $W_2$ be the no. of boys , D_2 be the no. of days and $H_2$ be the no. of hours.

$M_1=36\\W_1=48\\H_1=16\\D_1=?$

ATQ

$\frac{M_1 \times D_1 \times H_1}{W_1}=\frac{M_2 \times D_2 \times H_2}{W_2}$

So,$\frac{20 \times 24 \times 18}{40}=\frac{36 \times ? \times 16}{48}\\\frac{20 \times 24 \times 18 \times 48}{40 \times 36 \times 16}=?\\18=?$

Hence 36 men can prepare 48 toys in 18 days working 16 hrs a day

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