what mass of KCL O3 in gram should be heated to produce 11.2 litres of O2 gas at NTP? explain numerically please
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Heya!!
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Balance the equation
2KCLO3 ____> 2KCL + 3O2
i.e
to get 3 mole of O2 , 2 mole of kClo3 required.
also, 3 mole of O2 = (3×22.4)L oxygen
= 67.2L oxygen
so,
to get 67.2 L oxygen 2 mole of KClO3 required.
so,
to get 11.2 L of 02 .... (2/67.2 )×11.2 = 0.33 mole of KCLO3 required.
molecular mass of kClO3 = 122.5g
i.e 1 mole of KCl03 = 122.5g
0.33 mole = (0.33× 122.5)g
hope it helps!!
#PhoeniXX
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