Question

20 metres deep well with diameter 14 m is that up and the dugout is evenly spread out to form a platform 22 m into 14 M around will find height of platform

Answer 1

volume of mud =volume of platform

volume of mud=volume of well

so,
Volume of cylindrical well=Volume of platform

$volume \: of \: well = \pi {r}^{2} h \\ \pi {(7)}^{2} \times 20$
$volume \: of \: platform = l \times b \times h \\ 14 \times 22 \times h$

since volumes are equal so,

$\pi {(7)}^{2} \times 20 = 14 \times 22 \times h \\ \frac{22}{7} \times 7 \times 7 \times 20 = 14 \times 22 \times h \\ h = 10$
$\red{\boxed{Height \:of\: platform\: is \:10}}$