Question

20 mL of a 0.125 M HCl solution were neutralised by 25 mL of a KOH solution. The equation
for the reaction is
HCl(aq) + KOH(aq)  KCl(aq) + H2O(l) (not balanced)
(a) How many moles of HCl were consumed? How many moles of KOH were neutralised? (c) How many moles of KOH were there in 25 mL of the KOH solution?
(d) Calculate the concentration in mol/L of the KOH solution. solution.

Answer 1

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