Question

20 ml of hcl sol require 19.85 ml of 0.01M naoh sol for complete neutralisation the molarity of hcl sol is

Answer 1

The equation for the reaction is:

 HCl + NaOH = NaCl + H2O

Mole ratio

HCl : NaOH = 1:1

 

No. of moles of NaOH = No. of moles of HCl

 

No. of moles of NaOH = Volume in litres x molarity

 

= (19.85/1000) x 0.01

= 0.0001985 moles

 

No. of moles of HCl = Volume in litres x molarity

              0.0001985 = (20/1000) x molarity

 

Molarity of HCl = 0.0001985/0.02

 

                        = 0.009925 M

Approximately: 

= 0.01M